Solve the system of equations:-5x+y-4z=602x+4y+3z=-126x-3y-2x=-52

Answer:The answer to your question is:x = -8; y = 1 ; z = -4Step-by-step explanation:Δ = [tex]\left[\begin{array}{ccc}-5&1&-4\\2&4&3\\6&-3&-2\end{array}\right][/tex]   = 40 + 24 + 18 - (-4 + 45 - 96)  = 82  + 55  = 137Δx = [tex]\left[\begin{array}{ccc}60&1&-4\\-12&4&3\\-52&-3&-2\end{array}\right][/tex]= - 480 - 144 - 156 - ( 24 - 540 + 832)= -780 -316= - 1096Δy = [tex]\left[\begin{array}{ccc}-5&1&-4\\2&4&3\\6&-3&-2\end{array}\right][/tex]= 40 + 24 + 18 - ( - 4 + 45 - 96)= 82 + 55= 137Δz = [tex]\left[\begin{array}{ccc}-5&1&60\\2&4&-12\\6&-3&-52\end{array}\right][/tex]= 1040 - 360 - 72 - ( - 104 - 180 + 1440)= 608 - 1156= -548x = -1096/ 137 = -8y = 137 / 137 = 1z = -548 / 137 = -4