Help Me Please!!!The following picture is a square pyramid where AE= 6√2 cm and ∠EAB = 45°.Find the surface area of the pyramid. (Make sure you include formulas and numbers in the formulas as part ofyour solution. Also, include units in your final answer)

Answer:The surface area is [tex]288\ cm^{2}[/tex]Step-by-step explanation:we know thatThe surface area of the square pyramid is equal to the area of the square base plus the area of its four triangular lateral facesso[tex]SA=b^{2} +4[(\frac{1}{2}) (b)(h)][/tex]whereb is the length side of the square baseh is the height of each lateral triangular facewe know that[tex]\frac{b}{2}=h[/tex] -----> by angle of 45 degrees[tex]sin(45\°)=\frac{h}{6\sqrt{2}}[/tex][tex]h=6\sqrt{2}(sin(45\°)[/tex][tex]h=6\ cm[/tex]Find the value of b[tex]b=2h=2(6)=12\ cm[/tex]Find the surface area[tex]SA=12^{2} +4[(\frac{1}{2}) (12)(6)]=288\ cm^{2}[/tex]